8x^2+10=202

Solution for 8x^2+10=202 equation:

8x^2+10=202

We move all terms to the left:

8x^2+10-(202)=0

We add all the numbers together, and all the variables

8x^2-192=0

a = 8; b = 0; c = -192;
Δ = b2-4ac
Δ = 02-4·8·(-192)
Δ = 6144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6144}=\sqrt{1024*6}=\sqrt{1024}*\sqrt{6}=32\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{6}}{2*8}=\frac{0-32\sqrt{6}}{16}
=-\frac{32\sqrt{6}}{16}
=-2\sqrt{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{6}}{2*8}=\frac{0+32\sqrt{6}}{16}
=\frac{32\sqrt{6}}{16}
=2\sqrt{6}
$